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Question

For the following differential equation givne below indicate its order and degree (when defined)

d2ydx2+5x(dydx)26y=logx

(dydx)34(dydx)2+7y=sinx

d4ydx4sind3ydx3=0

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Solution

The given differential equations is
d2ydx2+5x(dydx)26y=logx
​​​​d2ydx2+5x(dydx)26y=logxd2ydx2+5x(dydx)26ylogx=0
As the order of the highest order derivative that occurs in the given differential equation is d2ydx2. Thus, its order is 2. Also index of the highest order derivation d2ydx2 is one. Hence, degree of the given differential equations is 1.

Note:In any differential equation, if a derivative is not in a polynomial equation, then we can find the order but degree cannot be determined.

The given differential equations is
(dydx)34(dydx)2+7y=sinx(dydx)34(dydx)2+7ysinx=0
As the highest order derivative that occurs in the given differential equation is dydx, thus order of the equations is 1 and its degree is 3.
(The highest power of dydx, which occurs (dydx))

Note:In any differential equation, if a derivative is not in a polynomial equation, then we can find the order but degree cannot be determined.

The given differential equations is
d4ydx4sin(d3ydx3)=0
Since, the higest order derivative which occurs in the given differential equation is d4ydx4. Thus, order of the given equation is 4, as sin(d3ydx3) occurs in the equation is not a polynomial equation. Hence, degree is not defined.

Note:In any differential equation, if a derivative is not in a polynomial equation, then we can find the order but degree cannot be determined.


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