For the following (i) I− (ii) Cl− (iii) Br− the increasing order of nucleophilicity would be:
A
Br−<Cl−<I−
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B
I−<Cl−<Br−
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C
Cl−<Br−<I−
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D
I−<Br−<Cl−
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Solution
The correct option is DI−<Br−<Cl− The increasing order of nucleophilicity would be I−<Br−<Cl−. Small sized Cl− is more nucleophilic than large sized I− as larger I− ion can better accomodate negative charge.