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Question

For the following
(i) I− (ii) Cl− (iii) Br−
the increasing order of nucleophilicity would be:

A
Br<Cl<I
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B
I<Cl<Br
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C
Cl<Br<I
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D
I<Br<Cl
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Solution

The correct option is D I<Br<Cl
The increasing order of nucleophilicity would be I<Br<Cl.
Small sized Cl is more nucleophilic than large sized I as larger I ion can better accomodate negative charge.

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