The correct option is C X=B+(¯¯¯¯¯¯¯¯¯¯¯¯A⋅B)
From the logic gates circuit, the input to OR gates are, output of NAND gate i.e. ¯¯¯¯¯¯¯¯¯¯¯¯A⋅B and B.
So, the required expression for output is,
X=(¯¯¯¯¯¯¯¯¯¯¯¯A⋅B)+B.
Hence, (A) is the correct answer.