You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Reaction Quotient

For the follo...

Question

For the following reaction, $1 g$ mole of $C a {C O}_{3}$ is enclosed in $5 L$ container.

$C a {C O}_{3} (s) ⟶ C a O (s) + {C O}_{2} (g)$

$K_{p} = 1.16$ at $1073 K$ , then percentage dissociation of $C a {C O}_{3}$ is:

0 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.58 %

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

65 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $6.58 %$
$C a {C O}_{3} (s) ⟶ C a O (s) + {C O}_{2} (g)$

$K_{p} = p_{{C O}_{3}}$ (only gaseous molecule count)

$K_{p} = K_{c} {(R T)}^{Δ n}$

By putting all the given values, on the above equation
$1.16 = \frac{x}{5} {(0.0821 \times 1073)}^{1}$

$x = \frac{1.16 \times 5}{0.0821 \times 1073} = 0.0658$

$= 0.0658 \times 100 = 6.58 %$

So, the correct option is $B$

Suggest Corrections

Similar questions

Q. For the reaction

1 g

mole of

C a {C O}_{3}

is enclosed in

5 L

container

C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g); K_{p} = 1.16 a t m

1073 K

then percentage dissociation of

C a {C O}_{3}

is:

50 g C a C O_{3}

are heated to

1073 K

in a

5 L

vessel. What percentage of

C a C O_{3}

would decompose at equilibrium? The value of

K_{p}

for the reaction.

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)

1.15 a t m

1073 K

Q. For the reaction,

C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)

K_{p} = 1.16 a t m

800^{o} C

. If

20.0 g

C a {C O}_{3}

were kept in a

10 L

container and heated up to

800^{o} C

, what percentage of

C a {C O}_{3}

would remain unreacted at equilibrium?

Q. For the reaction :

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g), K_{p} = 1

atm at

927^{o} C

. If 20g of

C a C O_{3}

were kept in a 10 litre vessel at

927^{o} C

, then calculate percentage of

C a C O_{3}

remaining at equilibrium:

Q. What is minimum mass (in g) of

C a C O_{3} (s)

will be required to establish the equilibrium

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)

1000 K

in a

4 L

container previously containing

C O_{2}

0.82 a t m

. Equilibrium constant

K_{P}

for the dissociation reaction

1.64 a t m

Join BYJU'S Learning Program

For the following reaction, 1g mole of CaCO3 is enclosed in 5L container.CaCO3(s)⟶CaO(s)+CO2(g)Kp=1.16 at 1073K, then percentage dissociation of CaCO3 is:

The correct option is B 6.58%CaCO3(s)⟶CaO(s)+CO2(g)Kp=pCO3(only gaseous molecule count)Kp=Kc(RT)ΔnBy putting all the given values, on the above equation 1.16=x5(0.0821×1073)1x=1.16×50.0821×1073=0.0658=0.0658×100=6.58%So, the correct option is B

For the following reaction, $1 g$ mole of $C a {C O}_{3}$ is enclosed in $5 L$ container.

$C a {C O}_{3} (s) ⟶ C a O (s) + {C O}_{2} (g)$

$K_{p} = 1.16$ at $1073 K$ , then percentage dissociation of $C a {C O}_{3}$ is: