For the following reaction at a particular temperature- according to the equations- 2 N 2 O 5 - 4N O 2 - O 2 2N O 2 - 1 2 O 2 - N 2 O 5The activation energies are E 1 and E 2 respectively- Then-

The correct option is A E _ 1 > E _ 2 Reaction one shows more activation energy #160;and the reaction 2nd shows the less activation energyActivation ene ...

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Standard XII

Chemistry

Le Chatelier's Principle for Del N Lesser Than Zero

For the follo...

Question

For the following reaction at a particular temperature, according to the equations:
$2 N_{2} O_{5} ⟶ 4 N O_{2} + O_{2}$
$2 N O_{2} + \frac{1}{2} O_{2} ⟶ N_{2} O_{5}$
The activation energies are $E_{1}$ and $E_{2}$ respectively. Then:

E_{1} > E_{2}

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E_{1} < E_{2}

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E_{1} = 2 E_{2}

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\sqrt{E_{1} E_{2}^{2}} = 1

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Solution

The correct option is A $E_{1} > E_{2}$
Reaction one shows more activation energy and the reaction 2nd shows the less activation energy
Activation energy is more for forward reaction so reaction 1 is forward reaction

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Similar questions

Q. For the following reaction at a particular temperature, according to the equations,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

2 N O_{2} + 1 / 2 O_{2} \to N_{2} O_{5}

the activation energies are

E_{1}

and

E_{2}

respectively, then:

Q. Consider the two equations at a particular temperature ;

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2}

E_{1}

and

E_{2}

represents the activation energy for the first and second reaction respectively then :

Q. For the reaction,

N_{2} + 3 H_{2} ⟶ 2 N H_{3}

. If

E_{1}

and

E_{2}

are equivalent masses of

N H_{3}

and

N_{2}

respectively, then

E_{1} - E_{2}

is :

Q. For the reaction,

N_{2} + 3 H_{2} \to 2 N H_{3}, i f E_{1} a n d E_{2}

are the equivalent masses of

N H_{3} a n d N_{2}

respectively, then

E_{1} - E_{2}

is:

Q. The following figure represents the liquid drop model of nuclear fission. The energies of these states are

E_{1}, E_{2} a n d E_{3}

respectively. Which option is correct?

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For the following reaction at a particular temperature, according to the equations: 2N2O5⟶4NO2+O2 2NO2+12O2⟶N2O5The activation energies are E1 and E2 respectively. Then:

The correct option is A E1>E2Reaction one shows more activation energy and the reaction 2nd shows the less activation energyActivation energy is more for forward reaction so reaction 1 is forward reaction

For the following reaction at a particular temperature, according to the equations:
$2 N_{2} O_{5} ⟶ 4 N O_{2} + O_{2}$
$2 N O_{2} + \frac{1}{2} O_{2} ⟶ N_{2} O_{5}$
The activation energies are $E_{1}$ and $E_{2}$ respectively. Then:

The correct option is A $E_{1} > E_{2}$
Reaction one shows more activation energy and the reaction 2nd shows the less activation energy
Activation energy is more for forward reaction so reaction 1 is forward reaction