For the following reaction C diamond - O 2- CO 2 g - - H -94-3 kcalC graphite - O 2- CO 2 g - - H -97-6 kcalThe heat required to change 1 g of C diamond - C graphite isA- 0-1375 kcalB- 1-59 kcalC- 0-55 kcalD- 0-275 kcal

The correct option is D 0.275 kcal C_diamond + O_2 → CO_2(g);Δ H = 94.3 kcal C_graphite + O_2 → CO_2(g);Δ H = 97.6 kcal C_diamond → C_graphite Δ ...

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Introduction

For the follo...

Question

For the following reaction

$C_{d i a m o n d} + O_{2} \to C O_{2} (g)$ ; $Δ H = - 94.3 k c a l$

$C_{g r a p h i t e} + O_{2} \to C O_{2} (g)$ ; $Δ H = - 97.6 k c a l$

The heat required to change 1 g of $C_{d i a m o n d} \to C_{g r a p h i t e}$ is

1.59 kcal

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0.1375 kcal

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0.55 kcal

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0.275 kcal

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C_{D i a m o n d} + O_{2} \to C O_{2} (g); Δ H = - 94.3 k c a l

C_{G r a p h i t e} + O_{2} \to C O_{2} (g); Δ H = - 97.6 k c a l

C_{d i a m o n d} \to C_{g r a p h i t e}

Calculate $Δ H$ for $C_{(g r a p h i t e)} \to C_{d i a m o n d}$ from the following data:

i) $C (g r a p h i t e) + O_{2} \to C O_{2} (g), Δ H = - 94 K c a l$

ii) $C (d i a m o n d) + O_{2} \to C O_{2} (g), Δ H = - 68 K c a l$

Δ H

C (d i a m o n d) + O_{2} \to C O_{2} (g); Δ H = - 94.5 K c a l

C (g r a p h i t e) + O_{2} \to C O_{2} (g); Δ H = - 94 K c a l

C (d i a m o n d, s) + O_{2} (g) \to C O_{2} (g); △ H = - 94.3 k c a l

C (g r a p h i t e, s) + O_{2} (g) \to C O_{2} (g); △ H = - 97.6 k c a l

C (d i a m o n d, s) \to C (g r a p h i t e, s)

C_{d i a m o n d} \to C_{(g r a p h i t e)}

(i n k c a l)

C_{(d i o m o n d)} + O_{2} (g) \to C O_{2} (g) . . . (i) (Δ H = - 94.5 k c a l) C_{(g r a p h i t e)} + O_{2} (g) \to C O_{2} (g) . . . (i i) (Δ H = - 94.0 k c a l)

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