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Reaction Quotient

For the follo...

Question

For the following reaction:
$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$
$0.4 m o l$ of $P C l_{5} (g)$ , $0.2 m o l$ of $P C l_{3} (g)$ and $0.6 m o l$ of $C l_{2} (g)$ are taken in a $1 L$ flask.
If $K_{c} = 0.2$ , then the direction in which reaction proceeds is :

A

Towards reactant side

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B

Towards products side

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C

Reaction is at equilibrium

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D

None of the above

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Solution

The correct option is A Towards reactant side
Given Reaction is:
$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$
$C o n c e n t r a t i o n = \frac{M o l e s}{V o l u m e}$
$[P C l_{5}] = \frac{0.4}{1} = 0.4 M [P C l_{3}] = \frac{0.2}{1} = 0.2 M [C l_{2}] = \frac{0.6}{1} = 0.6 M$
Finding $Q_{c}$
$Q_{c} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]}$

puttting the values,
$Q_{c} = \frac{0.2 \times 0.6}{0.4} = 0.3 M > K_{c} (= 0.2)$
Since, $Q > K_{c}$ the reaction proceeds in backward direction i.e. reactant $(P C l_{5})$ side.

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Similar questions

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Reaction Quotient

Standard XII Chemistry

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