Question

For the following reactions:

$(N{H}_4{)}_{2}S{O}_4+NaOH\stackrel{40\%}{\to }N{a}_{2}S{O}_4+H_{2}O+N{H}_3$
$N{H}_3+HCl\stackrel{80\%}{\to }N{H}_{4}Cl$

Choose the correct option(s) assuming all other reactants required are in sufficient amount.

• A. Produced mass of $N{H}_{4}Cl$ is $2.71$ g if $4$ g of $NaOH$ is taken.
• B. $41.25$ g of $(N{H}_4{)}_{2}S{O}_4$ is required to produce $10.7$ g of $N{H}_{4}Cl$.
• C. $25$ g of $NaOH$ is required to produce $10.7$ g of $N{H}_{4}Cl$.
• D. Produced moles of $N{H}_{4}Cl$ (in $I{I}^{nd}$ reaction) is $1.6$ times of produced moles of $N{a}_{2}S{O}_4$ (in $I^{st}$ reaction) if $4$ g of $NaOH$ is taken.

Answer 1

Answer: (B), (C), (D)

The correct options are
B $41.25$ g of $(N{H}_4{)}_{2}S{O}_4$ is required to produce $10.7$ g of $N{H}_{4}Cl$.
C $25$ g of $NaOH$ is required to produce $10.7$ g of $N{H}_{4}Cl$.
D Produced moles of $N{H}_{4}Cl$ (in $I{I}^{nd}$ reaction) is $1.6$ times of produced moles of $N{a}_{2}S{O}_4$ (in $I^{st}$ reaction) if $4$ g of $NaOH$ is taken.

The balanced chemical reactions are given below:
$(N{H}_4{)}_{2}S{O}_4+2NaOH\stackrel{40}{\to }N{a}_{2}S{O}_4+2H_{2}O+2N{H}_3$
$N{H}_3+HCl\stackrel{80}{\to }N{H}_{4}Cl$
(A) Mass of ammonium sulfate produced from $4$ g of $NaOH$ is $0.032\times 132.14=4.2$ g. Thus, option A is incorrect.
(B) Amount of ammonium sulfate required to produce $10.7$ g of ammonium chloride is $10.7\times \frac{132.14}{2\times 53.491}\times \frac{100}{80}\times \frac{100}{40}=41.25$ g.
(C) Amount of $NaOH$ required to produce $10.7$ g of ammonium chloride is $10.7\times \frac{2\times 40}{2\times 53.491}\times \frac{100}{80}\times \frac{100}{40}=25$ g.
(D) $4$ g $NaOH$ ($0.1$ mol) will produce $0.1\times \frac{1}{2}\times \frac{40}{100}=0.02moles$.
Moles of ammonium chloride produced $=0.02\times 2\times \frac{80}{100}=0.032$ moles.
Thus, produced moles of $N{H}_{4}Cl$ (in $I{I}^{nd}$ reaction) is $1.6$ times of produced moles of $N{a}_{2}S{O}_4$ (in $I^{st}$ reaction) if $4$ g of $NaOH$ is taken.
Hence, option B, C and D are correct.