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Question

For the following set, state with reasons whether it is a null set.
B={b|bN,2b+1 is even}

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Solution

Set B is a null set because for every natural number b,(2b+1) is an odd number.
Let's take one example,
After putting b=3 in 2b+1 we get 2(3)+1=7,which is a odd number.
Let's take another example, after puttingb=7 in2b+1 we get 2(7)+1=15which is an odd number.
Hence, B is a null set for every natural number.




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