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Question

For the force-displacement graph for a particle is as shown below. If the particle has mass of 2 kg and has initial velocity of 2 m/s, calculate final kinetic energy of particle, when it displaces from x=1 m to x=5 m.


A
24 J
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B
10 J
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C
30 J
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D
0 J
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Solution

The correct option is A 24 J
According to work energy theorem we know that,
Change in kinetic energy = Net work done.

We also know that net work done is
= Area under FS curve

=Area of part I +Area of part II Area of part III + Area of part IV

=(10×1)+(20×1)(20×1)+(10×1)
=20 J

Hence the change in kinetic energy
KfKi=20 J
Given m=2 kg,u=2 m/s
then Ki=mu22=4 J
Kf4=20 J
Kf=24 J
Option A is the correct answer

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