For the force-displacement graph for a particle is as shown below. If the particle has mass of 2kg and has initial velocity of 2m/s, calculate final kinetic energy of particle, when it displaces from x=1m to x=5m.
A
24J
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B
10J
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C
30J
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D
0J
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Solution
The correct option is A24J According to work energy theorem we know that, Change in kinetic energy = Net work done.
We also know that net work done is = Area under F−S curve
=Area of part I+Area of part II−Area of part III+ Area of part IV
=(10×1)+(20×1)−(20×1)+(10×1) =20J
Hence the change in kinetic energy Kf−Ki=20J Given m=2kg,u=2m/s then Ki=mu22=4J ⇒Kf−4=20J ⇒Kf=24J Option A is the correct answer