Question

For the four-bar linkage shown in the figure, the angular velocity of link AB is 1 rad/s. The length of link CD is 1.5 times the length of link AB. In the configuration shown, the angular velocity of link CD in rad/s is

• A. 1
• B. 3/2
• C. 1
• D. 2/3

Answer 1

The correct option is D 2/3


Let the length of link AB be x velocity diagram ;

$V_b=V_c$
(As per velocity diagram)
$AB\times {\omega }_{AB}=CD\times {\omega }_{CD}$

$1=\left(\frac{CD}{AB}\right)\times {\omega }_{CD}$

$1=1.5\times {\omega }_{CD}$

${\omega }_{CD}=\frac{2}{3}$ rad/s