Question

For the four circles $M,N,O$ and $P,$ following four equations are given:
Circle $M:x^2+y^2=1$
Circle $N:x^2+y^2–2x=0$
Circle $O:x^2+y^2–2x–2y+1=0$
Circle $P:x^2+y^2–2y=0$
If the centre of circle $M$ is joined with centre of the circle $N,$ further centre of circle $N$ is joined with centre of the circle $O,$ centre of circle $O$ is joined with the centre of circle $P$ and lastly, centre of circle $P$ is joined with centre of circle $M,$ then these lines form the sides of a :

• A. Rectangle
• B. Square
• C. Parallelogram
• D. Rhombus

Answer 1

The correct option is B Square

$C_M=(0,0)$
$C_N=(1,0)$
$C_O=(1,1)$
$C_P=(0,1)$