For the frequency distribution-Variate x- x1 x2 x3- x15Frequency fx- f1 f2 f3- f15where 00- the standard deviation cannot be-

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Spearman's Rank Coefficient

For the frequ...

Question

For the frequency distribution:
Variate $(x) : x_{1} x_{2} x_{3} \dots x_{15}$
Frequency $f (x) : f_{1} f_{2} f_{3} \dots f_{15}$
where $0 < x_{1} < x_{2} < x_{3} < . . . . < x_{15} = 10$ and $15 \sum i = 1 f_{i} > 0$ , the standard deviation cannot be:

1

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6

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Solution

The correct option is C $6$
$σ^{2} \leq \frac{1}{4} {(M - m)}^{2}$
Where $M$ and $m$ are the upper and lower bounds of values of any random variable respectively.
$\Rightarrow σ^{2} \leq \frac{1}{4} {(10 - 0)}^{2}$
$\Rightarrow σ^{2} < 25$
$\Rightarrow - 5 < σ < 5$
$∴ σ \neq 6$

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For the frequency distribution: Variate (x): x1 x2 x3⋯x15 Frequency f(x): f1 f2 f3⋯f15 where 0<x1<x2<x3<....<x15=10 and 15∑i=1fi>0, the standard deviation cannot be:

The correct option is C 6σ2≤14(M−m)2 Where M and m are the upper and lower bounds of values of any random variable respectively. ⇒σ2≤14(10−0)2 ⇒σ2<25 ⇒−5<σ<5 ∴σ≠6

For the frequency distribution:
Variate $(x) : x_{1} x_{2} x_{3} \dots x_{15}$
Frequency $f (x) : f_{1} f_{2} f_{3} \dots f_{15}$
where $0 < x_{1} < x_{2} < x_{3} < . . . . < x_{15} = 10$ and $15 \sum i = 1 f_{i} > 0$ , the standard deviation cannot be:

The correct option is C $6$
$σ^{2} \leq \frac{1}{4} {(M - m)}^{2}$
Where $M$ and $m$ are the upper and lower bounds of values of any random variable respectively.
$\Rightarrow σ^{2} \leq \frac{1}{4} {(10 - 0)}^{2}$
$\Rightarrow σ^{2} < 25$
$\Rightarrow - 5 < σ < 5$
$∴ σ \neq 6$