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Byju's Answer
Standard XII
Mathematics
Theorems for Differentiability
For the funct...
Question
For the function
f
(
x
)
=
e
x
,
a
=
0
,
b
=
1
, the value of c in mean value theorem will be
A
log x
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B
log (e-1)
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C
1
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Solution
The correct option is
B
log (e-1)
Here
f
(
b
)
−
f
(
a
)
b
−
a
=
f
(
c
)
⇒
e
b
−
e
a
b
−
a
=
f
(
c
)
⇒
e
−
1
1
−
0
=
e
c
⇒
c
=
l
o
g
(
e
−
1
)
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