Question

For the gas phase decomposition:
$PC{l}_5\left(g\right)\stackrel{\Delta }{\rightleftharpoons }PC{l}_3\left(g\right)+C{l}_2\left(g\right)$

• A. $\Delta H<0,\Delta S<0$
• B. $\Delta H>0,\Delta S>0$
• C. $\Delta H>0,\Delta S<0$
• D. $\Delta H<0,\Delta S>0$

Answer 1

The correct option is A $\Delta H<0,\Delta S<0$

For a equilibrium reaction, $\Delta G=0$

So $\Delta H=T\times S$

As the moles in product side are more so entropy increased and according to the formula $H$ depend upon the $S$. So, both are increasing.