For the gas phase reaction, $C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6}; [△ H = - 32.7 k c a l]$
Carried out in a vessel, the equilibrium concentration of $C_{2} H_{4}$ can be increased by:

increasing the pressure

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increasing the temperature

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removing some

C_{2} H_{6}

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adding some

H_{2}

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Solution

The correct option is B increasing the temperature
Since $Δ H < 0$ , it is an exothermic reaction and according to le Chatelier's principle in an exothermic reaction increase in temperature favours backward reaction which will increase the concentration of $C_{2} H_{4}$

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Similar questions

Q. For the gas phase reaction,

C_{2} H_{4} + H_{2}

⇌

C_{2} H_{6}

(Δ H = - 32.7 k c a l)

, carried out in a closed vessel. The equilibrium concentration of

C_{2} H_{4}

can be increased by?

For the gas phase reaction $C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6},$ $Δ H$ = -32.7kcal carried out in a vessel, the equilibrium concentration of $C_{2} H_{4}$ can be increased by -

Q. For the Gas phase reaction

C_{2} H_{4} (g) + H_{2} (g) \to C_{2} H_{6} (g) △ H = - 32.7 k c a l

caried out in a vessel, the equilibrium concentration of

C_{2} H_{4}

can be increased by:

Q. For the gas phase reaction,

C_{2} H_{4} (g) + H_{2} (g) ⇌ C_{2} H_{6} (g); △ H^{o} = - 136.8 k J m o l^{- 1}

carried out in a vessel, the equilibrium concentration of

C_{2} H_{4}

can be increased by:

For the gas phase reaction $C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6},$ DH = -32.7kcal carried out in a vessel, the equilibrium concentration of $C_{2} H_{4}$ can be increased by -

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For the gas phase reaction, C2H4+H2⇌C2H6;[△H=−32.7 kcal]Carried out in a vessel, the equilibrium concentration of C2H4 can be increased by:

The correct option is B increasing the temperatureSince ΔH<0, it is an exothermic reaction and according to le Chatelier's principle in an exothermic reaction increase in temperature favours backward reaction which will increase the concentration of C2H4

For the gas phase reaction, $C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6}; [△ H = - 32.7 k c a l]$
Carried out in a vessel, the equilibrium concentration of $C_{2} H_{4}$ can be increased by:

The correct option is B increasing the temperature
Since $Δ H < 0$ , it is an exothermic reaction and according to le Chatelier's principle in an exothermic reaction increase in temperature favours backward reaction which will increase the concentration of $C_{2} H_{4}$