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Question

For the gaseous reaction, K+FK++F, ΔH=19kcal/mol under conditions when cations and anions are prevented by electrostatic separation from combining with each other. The IE1 of K is 4.3eV.
Electron gain enthalpy of F is X.
Find - X ( nearest integer value).

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Solution

K+FK++F;ΔH=19kcal
ΔH=IE+Ega1....(i)
ΔH=19×103calmol1=19×103×4.186.023×1023J/molecule
=19×103×4.186.023×1023×1.602×1019eV
ΔH=0.823eV
By eq. (i) 0.823=4.3+Ega1........(ii)
orEga1=3.477eV

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