wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the gaseous reaction
N2+3H22NH3
The partial pressure of H2 and N2 are 0.4 and 0.8 atm respectively. The total pressure of the entire system is 2.80 atm. The equilibrium constant Kp will be:

A
50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.02
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
250
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
31.25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 50
N2+3H22NH3

Given that,
Partial pressure of N2=0.8 atm
Partial pressure of H2=0.4 atm
Total pressure =2.8 atm

Thus, partial pressure of NH3=Total pressure(PN2+PH2)

PNH3=2.8 atm(0.8+0.4) atm=1.6 atm

KP=[PNH3]2[PH2]3[PN2]=[1.6]2[0.4]3[0.8]=50

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Le Chateliers Principle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon