Question

For the gaseous reaction $N_2{O}_4\left(g\right)\iff 2N{O}_2\left(g\right)$

• A. $\Delta H>\Delta E$
• B. $\Delta H<\Delta E$
• C. $\Delta H=\Delta E$
• D. $\Delta H\ge \Delta E$

Answer 1

The correct option is A $\Delta H>\Delta E$

$N_2{O}_4\left(g\right)\to 2N{O}_2\left(g\right)$
$\Delta n_g=2-1$
$=$ 1
$\Delta H=\Delta E+\Delta n_{g}RT$
$\Delta H=\Delta E+RT$
$\therefore \Delta H>\Delta E$

Option A is correct.