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Effective Equilibrium Constant

For the gaseo...

Question

For the gaseous reaction, the equilibrium constant is given:
$X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F; K_{1}$

$X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}; K_{2}$

Then, the equilibrium constant for the reaction given below is:
$X e O_{4} + 2 H F ⇋ X e O_{3} F_{2} + H_{2} O$

A

\frac{K_{1}}{K_{2}}

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B

\frac{K_{1}}{K_{2}^{2}}

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C

\frac{K_{1}^{2}}{K_{2}}

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D

\frac{K_{2}}{K_{1}}

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Solution

The correct option is D $\frac{K_{2}}{K_{1}}$
$X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F; K_{1}$
Reversing the equation, we get
$X e O F_{4} + 2 H F ⇌ X e F_{6} + H_{2} O; \frac{1}{K_{1}} . . . . . (i)$

$X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}; K_{2} . . . . (i i)$

Adding $e q^{n} (i)$ and $e q^{n} (i i)$ , we get
$X e O_{4} + 2 H F ⇌ X e O_{3} F_{2} + H_{2} O; K = \frac{K_{2}}{K_{1}}$

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Similar questions

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

= k_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

= K_{2}

. Then equilibrium constant for the following reaction will be:

X e O_{4} + 2 H F ⇌ X e O_{3} F_{2} + H_{2} O

.

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

= K_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

= K_{2}

. Then equilibrium constant for the following reaction will be:

- X e O_{4} + 2 H F ⇌ X e O_{4} F_{2} + H_{2} O

.

Q. Consider the following gaseous equilibria with equilibrium constants

K_{1}

K_{2}

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g) 2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

The equilibrium constants are related as :

Q. Two gaseous equilibria

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

have equilibrium constants

K_{1}

K_{2}

respectively at

298 K

. Which of the following relationships between

K_{1}

K_{2}

K_{1}

K_{2}

are the respective equilibrium constants for the two reactions:
(i)

X e F_{6} (g) + H_{2} O (g) ⇌ X e O F_{4} (g) + 2 H F (g)

X e O_{4} (g) + X e F_{6} (g) ⇌ X e O F_{4} (g) + X e O_{3} F_{2} (g)

then the equilibrium constant for the reaction:

X e O_{4} (g) + 2 H F (g) ⇌ X e O_{3} F_{2} (g) + H_{2} O (g)

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