Question

For the given AC circuit phase difference between current $I_1$ and $I_2$ is

• A. $ta{n}^{-1}\left(\frac{X_L}{R}\right)+\frac{\pi }{2}$
• B. $ta{n}^{-1}\left(\frac{X_C}{R}\right)-\frac{\pi }{2}$
• C. $ta{n}^{-1}\left(\frac{X_L}{R}\right)+ta{n}^{-1}\left(\frac{X_C}{R}\right)$
• D. Zero

Answer 1

The correct option is C $ta{n}^{-1}\left(\frac{X_L}{R}\right)+ta{n}^{-1}\left(\frac{X_C}{R}\right)$


Phase difference $={\theta }_1+{\theta }_2$