For the given cell reaction
$F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}$
The equilibrium constant is:
(Given: $E_{C e^{4 +} | C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} | F e^{2 +}}^{o} = 0.68 V$ )

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Solution

Given:
$E_{C e^{4 +} / {C e}^{3 +}}^{\circ} = 1.44 V E_{{F e}^{3 +} / {F e}^{2 +}}^{\circ} = 0.68 V E_{c e l l}^{\circ} = E_{r e d u c t i o n}^{\circ} - E_{o x i d a t i o n}^{\circ} = 1.44 - 0.68 = 0.76 V {Δ G}^{⊖} = - R T ln K Δ G^{⊖} = - n F E_{c e l l}^{\circ} - n F E_{c e l l}^{\circ} = - R T ln K ln K = \frac{n F E_{c e l l}^{\circ}}{R T} {log}_{10} K = \frac{n F E_{c e l l}^{\circ}}{2.303 R T} {log}_{10} K = \frac{1 \times 96500 \times 0.76}{2.303 \times 8.314 \times 298}$
$K$ , equilibrium constant $= 7.136 \times 10^{12}$

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Similar questions

F e^{2 +} + C e^{4 +} ⇌ C e^{3 +} + F e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{\circ} = 1.44 V

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.68 V

\frac{2.303 R T}{F} = 0.06

25^{o} C, l o g 4.68 = 0.67

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{{C e}^{4 +} / C e^{3 +}}^{\circ} = 1.44 V; E_{F e^{2 +} / F e^{3 +}}^{\circ} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{0} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.68 V]

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} | F e^{3 +} + C e^{3 +}

E^{0} C e^{4 +} / C e^{3 +} = 1.44

E^{0} F e^{3 +} / F e^{2 +} = 0.68 V]

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