For the given charge distribution, the net electric field at the centre of the non-conducting ring is
A
180N/C
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B
220N/C
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C
320N/C
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D
360N/C
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Solution
The correct option is D360N/C Given: λ1=10nC/m=10×10−9C;R=1m λ2=−10nC/m=−10×10−9C.
Electric field due to upper half will be directed toward OB and also, electric field due to lower half will be directed toward OB.
Electric field due to arc of a circle, E=2kλRsinα2
Electric field due to semicircle at the centre, α=180∘ ⇒E=2kλR