Question

For the given circuit answer correct options.

• A. Impedance of circuit is $10\sqrt{5}\Omega$
  
• B. Impedance of circuit is $\frac{110}{3}\Omega$
  
• C. Current leads source voltage
  
• D. Source voltage leads current.

Answer 1

Answer: (A), (C)

The correct options are
A Impedance of circuit is $10\sqrt{5}\Omega$

C Current leads source voltage


$X_{L_1}=jw{L}_1=j20\Omega$

$X_c=\frac{1}{j{w}_c}=-j20\Omega$

$\frac{1}{Z_1}=\frac{1}{X{L}_1}+\frac{1}{X_C}=\frac{1}{J20}-\frac{1}{J10}$

$Z_1=-j20,X_{L_2}=jw{L}_2=j10\Omega$

$Z=R+Z_1+X_{L_2}=20+j10-j20=20-j10$

$|Z|=\sqrt{{20}^2+{10}^2}=10\sqrt{5}$
Circuit is capacitive. So, current is ahead of voltage.