For the given combination of gates, if the logic states of inputs A, B, C are as follows A = B = C = 0 and A = B = 1, C = 0 then the logic states of output D are
The output D for the given combination
D=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+B).C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+B)+¯¯¯¯C
If A=B=C=0 then D=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(0+0)+¯¯¯0=¯¯¯0+¯¯¯0 = 1 + 1 = 1
If A=B=1,C=0 then D=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(1+1)+¯¯¯0=¯¯¯1+¯¯¯0 = 0 + 1 = 1