Question

For the given compound number of $\pi$ electrons that take part in conjugation is/are:

Answer 1

The given compound is planar, has conjugation.
In this, only the peripheral pi bonds participate in conjugation and this type of conjugation is called peripheral conjugation. The middle double bond is a non-huckel$\pi$ bond and does not take part in conjugation. So, the number of$\pi$ electrons that take part in conjugation are 14.


Total number of$\pi e^{-}$ are$14$ i.e. it follows$(4n+2)\pi e^{-}$ huckel's rule.
and hence it is an aromatic compound.