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Standard XII

Chemistry

Limiting Reagent or Reactant

For the given...

Question

For the given cyclic process CAB as shown for a gas, the work done is :

1 J

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5 J

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10 J

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30 J

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Solution

The correct option is D $10 J$
Since PV indicator diagram is given, so work done by gas is area under the cyclic diagram.
$∴ Δ W =$ Work done by gas $= \frac{1}{2} \times 4 \times 5 J$
$= 10 J$

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For the given cyclic process CAB as shown for a gas, the work done is :

The correct option is D 10JSince PV indicator diagram is given, so work done by gas is area under the cyclic diagram.∴ΔW= Work done by gas =12×4×5J=10J

The correct option is D $10 J$
Since PV indicator diagram is given, so work done by gas is area under the cyclic diagram.
$∴ Δ W =$ Work done by gas $= \frac{1}{2} \times 4 \times 5 J$
$= 10 J$