For the given equations cos(4y−3x−2)−cos(4y+3x+2)=2+2ln(k4−255) and cos(4y−3x−2)+cos(4y+3x+2)=2k+8 to have real solutions (x,y), the possible value of k is
A
4
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B
-4
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C
-5
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D
none of these
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Solution
The correct option is B -4 2sin(4y)sin(3x+2)=2+2ln(k4−255)