Each part: 1 Mark
In the given figure,
In ΔBCA and ΔBTA,
BC = BT (Given)
CA = TA (Given)
BA = BA (Common side)
Thus, ΔBCA≅ΔBTA [By SSS congruence rule]
In ΔQRS and ΔTPQ,
QT = QS (Given)
PQ = RS (Given)
PT = QR (Given)
Thus, ΔQRS≅ΔTPQ [By SSS congruence rule]