The correct option is C x3−2x2
For Rolle's theorem to be applicable function should be continuous in [0,2] and differentiable in (0,2) and f(0)=f(2).
For options (a) and (b): Both are continuous and differentiable in the given interval but f(0)≠f(2), so not applicable.
For f(x)=tanx is discontinuous at x=π2
For f(x)=x3−2x2=x2(x−2), is continuous and differentiable everywhere also f(0)=f(2), so rolle's theorem is applicable.