For the given linear equation:
y - 3x + 1 = 0,
what are the values of y for x = [3, -4, 2]?
8,-13,5
We have y-3x+1= 0
For x = 3
⇒y−3(3)+1=0;y=8
For x = -4
⇒y−3(−4)+1=0;y=−13
For x = 2
⇒y−3(2)+1=0;y=5
Thus, the value of y for respective values of x are 8, -13 and 5.