For the given orthogonal matrix Q-Q - 3-7 2-7 6-7- -6-7 3-7 2-7- 2-7 6-7 -3-7 -The inverse is

∴ A is orthogonal so nbsp; Q Q^T=I ⇒ nbsp; Q^ T=Q^T nbsp; Hence Q^ 1= [ nbsp;3/7 amp; 6/7 amp;2/7; nbsp; nbsp;2/7 amp; 3/7 amp;6/7; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Orthogonal Matrix

For the given...

Question

For the given orthogonal matrix Q.
Q = $⎡ ⎢ ⎣ \begin{matrix} 3 / 7 & 2 / 7 & 6 / 7 - 6 / 7 & 3 / 7 & 2 / 7 2 / 7 & 6 / 7 & - 3 / 7 \end{matrix} ⎤ ⎥ ⎦$

The inverse is

⎡ ⎢ ⎣ \begin{matrix} 3 / 7 & 2 / 7 & 6 / 7 - 6 / 7 & 3 / 7 & 2 / 7 2 / 7 & 6 / 7 & - 3 / 7 \end{matrix} ⎤ ⎥ ⎦

No worries! We‘ve got your back. Try BYJU‘S free classes today!

⎡ ⎢ ⎣ \begin{matrix} - 3 / 7 & - 2 / 7 & - 6 / 7 6 / 7 & - 3 / 7 & - 2 / 7 - 2 / 7 & - 6 / 7 & 3 / 7 \end{matrix} ⎤ ⎥ ⎦

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Q = ⎡ ⎢ ⎣ \begin{matrix} 3 / 7 & - 6 / 7 & 2 / 7 2 / 7 & 3 / 7 & 6 / 7 6 / 7 & 2 / 7 & - 3 / 7 \end{matrix} ⎤ ⎥ ⎦

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

⎡ ⎢ ⎣ \begin{matrix} - 3 / 7 & - 6 / 7 & - 2 / 7 - 2 / 7 & - 3 / 7 & - 6 / 7 - 6 / 7 & - 2 / 7 & 3 / 7 \end{matrix} ⎤ ⎥ ⎦

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{4}{7} - \frac{5}{7^{2}} + \frac{4}{7^{3}} - \frac{5}{7^{4}} + \frac{4}{7^{5}} - \frac{5}{7^{6}} + . . . .

[\begin{matrix} x & y \\ z & u \end{matrix}]

[\begin{matrix} 5 & - 7 \\ - 2 & 3 \end{matrix}] [\begin{matrix} x & y \\ z & u \end{matrix}] = [\begin{matrix} - 16 & - 6 \\ 7 & 2 \end{matrix}]

\frac{1}{7} + \frac{2}{7^{2}} + \frac{3}{7^{3}} + . . . . . . . . .

{[{(\frac{5}{7})}^{2}]}^{3} \times 7^{6} \div {(5^{3})}^{2}

Join BYJU'S Learning Program