You visited us 1 times! Enjoying our articles? Unlock Full Access!

Graphs of Quadratic Equation for different values of D when a>0

For the given...

Question

For the given quadratic expression $y = a x^{2} + b x + c,$ if $a > 0 & D = 0,$ then the graph will intersect the $x -$ axis at

2

points.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

point.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

points.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1$ point.
For the given quadratic equation $y = a x^{2} + b x + c, a > 0$
This means that the graph is an upward opening parabola.
Also, $D = 0 \Rightarrow$ The equation will have only one root.
This means $y = 0$ at only one $x$ value.
$∴$ The graph cuts the $x$ axis at only one point.

Suggest Corrections

Similar questions

y = a x^{2} + b x + c,

a < 0 & D > 0,

x -

1

y = a x^{2} + b x + c,

a > 0 & D < 0,

x -

y = a x^{2} + b x + c, a \neq 0

x -

a x^{2} + b x + c = 0

y = a x^{2} + b x + c,

a > 0 & D < 0, y < 0

y = f (x) = a x^{2} + b x + c,

f (α) = 0

x, f (x) < 0.

a

D

Join BYJU'S Learning Program