Question

For the given quadratic expression $y=a{x}^2+bx+c,$ if $a>0\&D=0,$ then the graph will intersect the $x-$ axis at

• A. $1$ point.
• B. $2$ points.
• C. $0$ points.

Answer 1

The correct option is A $1$ point.

For the given quadratic equation $y=a{x}^2+bx+c,a>0$
This means that the graph is an upward opening parabola.
Also, $D=0\Rightarrow$ The equation will have only one root.
This means $y=0$ at only one $x$ value.
$\therefore$ The graph cuts the $x$ axis at only one point.