For the given reaction, 2A+3B+C→products
Order of reaction with respect to A, B and C are 3, 1 and 0 respectively. What will be the rate law of the given reaction?
A
R=K[A]2[B]3[C]
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B
R=K[A]2[B]3
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C
R=K[A]3[B]1[C]0
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D
R=[A][B]2[C]3
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Solution
The correct option is CR=K[A]3[B]1[C]0 Order of a reaction:
For a given reaction: aA+bB+cC→Products
If, Rate∝[A]p[B]q[C]r
Overall order of the reaction is : (p+q+r)
where,
p: order of reaction with respect to A
q: order of reaction with respect to B
r: order of reaction with respect to C
For, 2A+3B+C→products
Order of reeaction with respect to A is 3 Order of reeaction with respect to B is 1 Order of reeaction with respect to C is 0
Hence, the rate law of the reaction is R=K[A]3[B]1[C]0
Also, Order of reaction is=4