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Question

For the given reaction,
2A+3B+Cproducts
Order of reaction with respect to A, B and C are 3, 1 and 0 respectively. What will be the rate law of the given reaction?

A
R=K[A]2[B]3[C]
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B
R=K[A]2[B]3
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C
R=K[A]3[B]1[C]0
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D
R=[A][B]2[C]3
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Solution

The correct option is C R=K[A]3[B]1[C]0
Order of a reaction:
For a given reaction:
aA+bB+cCProducts
If,
Rate[A]p[B]q[C]r
Overall order of the reaction is :
(p+q+r)
where,
p: order of reaction with respect to A
q: order of reaction with respect to B
r: order of reaction with respect to C

For,
2A+3B+Cproducts

Order of reeaction with respect to A is 3
Order of reeaction with respect to B is 1
Order of reeaction with respect to C is 0

Hence, the rate law of the reaction is
R=K[A]3[B]1[C]0
Also,
Order of reaction is=4

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