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B
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C
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D
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Solution
The correct option is B On bromination of alkane a 3∘ halogenated product will be the major product.
On dehydrohalogenation with alcoholic KOH , major product will be that alkene which is more substituted and has more number of α-hydrogens.
Compound (a) has less α-hydrogens and is the minor product.
Compound (b) is the major product as shown: