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Ways to Define Concentration

For the given...

Question

For the given reaction, mole ratio of $C_{6} H_{12} O_{6}$ and $H_{2} S O_{4}$ present is $1 : 12$ .
$C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O$

A

True

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B

False

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Solution

The correct option is A True
Given equation :-
$C_{6} H_{12} O_{6} + 12 H_{2} {S O}_{4} ⟶ 6 {C O}_{2} + 12 {S O}_{2} + 18 H_{2} O$
Moles ratio of $\frac{C_{6} H_{12} O_{6}}{H_{2} {S O}_{4}} = \frac{1}{12}$
So, Given conclusion statement is true.

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Similar questions

Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
(Mass ratio of

C_{6} H_{12} O_{6}

H_{2} S O_{4}

1 : 12

Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
Mole ratio of

H_{2} O

C_{6} H_{12} O_{6}

present in reaction mixture is

18 : 1

Q. Consider the reaction,

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
Mass ratio of

H_{2} S O_{4}

C O_{2}

in reaction mixture is

2 : 1

Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
Number of moles of

H_{2} S O_{4}

S O_{2}

in the reaction mixture is always same

Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
Mole ratio of

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C O_{2}

2 : 1

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