Question

For the given uniformly charged quarter ring, the electric field along $x-$ axis is

• A. $150\text{N/C}$
• B. $160\text{N/C}$
• C. $170\text{N/C}$
• D. $180\text{N/C}$

Answer 1

The correct option is D $180\text{N/C}$

Given:
$\lambda =+20\text{nC/m}=+20\times {10}^{-9}\text{C/m};R=1\text{m}$

We know that, for a uniformly charged quarter ring, the electric field along the axis of ring is given by

$E_x=\frac{k\lambda }{R}$

$\Rightarrow E_x=\frac{9\times {10}^9\times 20\times {10}^{-9}}{1}$

$\Rightarrow E_x=180\text{N/C}$

Hence, option $\left(d\right)$ is correct.