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Byju's Answer
Standard XII
Physics
Electric Field Due to a Ring Along the Axis
For the given...
Question
For the given uniformly charged ring, magnitude of the net electric field at point
P
is
(in
N/C
) ( Round off your answer to the nearest integer value)
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Solution
We know that for a uniformly charged ring, the electric field along the axis at point
P
is given by,
E
x
=
k
Q
r
(
r
2
+
R
2
)
3
/
2
⇒
E
x
=
2
π
k
λ
R
r
(
r
2
+
R
2
)
3
/
2
(
∵
Q
=
λ
×
2
π
R
)
Here,
r
=
1
m
;
R
=
5
m
;
λ
=
+
10
nC/m
So,
E
x
=
2
×
3.14
×
9
×
10
9
×
10
×
10
−
9
×
5
×
1
(
1
2
+
5
2
)
3
/
2
⇒
E
x
=
21.3
N/C
and,
E
y
=
0
∴
E
n
e
t
=
√
E
2
x
+
E
2
y
=
√
21.3
2
+
0
2
=
21.3
N/C
Accepted answers:
21
,
21.0
,
21.00
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Q.
Assertion :For a non-uniformly charged thin circular ring with net charge zero, the electric field at any point on axis of the ring is zero. Reason: For a non-uniformly charged thin circular ring with net charge zero, the electric potential at each point on axis of the ring is zero.
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