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Question

For the given uniformly charged ring, magnitude of the net electric field at point P is (in N/C) ( Round off your answer to the nearest integer value)


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Solution

We know that for a uniformly charged ring, the electric field along the axis at point P is given by,

Ex=kQr(r2+R2)3/2

Ex=2πkλRr(r2+R2)3/2 (Q=λ×2πR)

Here,
r=1 m; R=5 m; λ=+10 nC/m

So,
Ex=2×3.14×9×109×10×109×5×1(12+52)3/2

Ex=21.3 N/C

and, Ey=0

Enet=E2x+E2y=21.32+02=21.3 N/C

Accepted answers: 21 , 21.0 , 21.00

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