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Propagation of Waves

For the given...

Question

For the given uniformly charged ring of linear charge density $+ 10 nC/m$ , the electric field in $y -$ direction at point $P$ is

200 N/C

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150 N/C

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Zero

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100 N/C

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Solution

The correct option is C Zero

For every small element of uniformly charged ring, there is small element on diameterically opposite side whose $y -$ component of electric field $(d E sin θ)$ cancels each other.
Therefore, $\int d E sin θ = 0$ along $y -$ direction.

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Propagation of Waves

Standard XII Physics

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For the given uniformly charged ring of linear charge density +10 nC/m, the electric field in y− direction at point P is

The correct option is C Zero For every small element of uniformly charged ring, there is small element on diameterically opposite side whose y− component of electric field(dEsinθ) cancels each other. Therefore, ∫dEsinθ=0 along y− direction.

For the given uniformly charged ring of linear charge density $+ 10 nC/m$ , the electric field in $y -$ direction at point $P$ is

The correct option is C Zero

For every small element of uniformly charged ring, there is small element on diameterically opposite side whose $y -$ component of electric field $(d E sin θ)$ cancels each other.
Therefore, $\int d E sin θ = 0$ along $y -$ direction.