For the given values of y, which values of x satisfy the linear equation y=x/3?

x=	12,	20,	28
y=	3,	5,	7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x=	6,	3,	9
y=	2,	1,	3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x=	6,	2,	4
y=	12,	4,	8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x=	30,	12,	6
y=	5,	2,	1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

x= 6, 3, 9

y= 2, 1, 3

The values for x should be 3 times the value of y, as the linear equation is y=x/3. For example, when x=3, y=1. Therefore the only option that satisfies this condition is option B.

Suggest Corrections

Similar questions

For the given linear equation $y - 3 x + 1 = 0,$ what are the values of $y$ if $x = [3, - 4, 2]$ ?

x

y

$x$	$6$	$- 6$
$y$	$- 2$	$6$

x, y

(i)

x

(i i)

y

⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 1 & 3 & 4 2 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦ ⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦ = ⎡ ⎢ ⎣ \begin{matrix} 6812 \end{matrix} ⎤ ⎥ ⎦

(x, y \in R)

(x + 2 y) + (2 x - 3 y) i + 4 i = 5

\begin{matrix} X & 6 & - 6 Y & - 2 & 6 \end{matrix}

Join BYJU'S Learning Program