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Value of a Polynomial

For the given...

Question

For the given values of y, which values of x satisfy the linear equation y=x/3?

x=	12,	20,	28
y=	3,	5,	7

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x=	6,	3,	9
y=	2,	1,	3

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x=	6,	2,	4
y=	12,	4,	8

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x=	30,	12,	6
y=	5,	2,	1

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Solution

The correct option is B

x= 6, 3, 9

y= 2, 1, 3

The values for x should be 3 times the value of y, as the linear equation is y=x/3. For example, when x=3, y=1. Therefore the only option that satisfies this condition is option B.

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For the given linear equation $y - 3 x + 1 = 0,$ what are the values of $y$ if $x = [3, - 4, 2]$ ?

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⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 1 & 3 & 4 2 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦ ⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦ = ⎡ ⎢ ⎣ \begin{matrix} 6812 \end{matrix} ⎤ ⎥ ⎦

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\begin{matrix} X & 6 & - 6 Y & - 2 & 6 \end{matrix}

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