wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the half-cell:

At pH=2, electrode potential is:

A
1.36 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.30 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.42 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.20 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.42 V
This is quinhydrone electrode and here we take equimolar mixture of mixture quinone and hydroquinone.

So in this electrode, concentration of A = concentration of B

From Nernst equation,
E=E0.0592 log[H+]2
Given, pH=2
[H+]=102
Hence, E=1.300.0592log104
E=1.30+0.118=1.4181.42

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrochemical Cell
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon