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Question


For the half cell Eo=1.30 V. At pH =3, electrode potential is:


19462_62eae8e2d3914eafb082bdaa9e60b967.png

A
1.30V
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B
1.20V
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C
1.10V
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D
1.48V
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Solution

The correct option is D 1.48V
In this equation: E=E00.05912log[H+]2

=E00.0591.log[H+]

=E0+0.0591 pH

=1.30+0.0591×3

=1.48 V

Hence, the correct option is D

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