For the half cell reaction- 2BrO3- - 12H- - 10e - Br2 - 6H2Othe equivalent mass of sodium bromate is

The correct option is D 1/5 of its mol. mass 2BrO_3^ + 12H^+ + 10e → Br_2 + 6H_2O During the above conversion bromate changed the oxidation number fr ...

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Standard XII

Chemistry

Faraday's Second Law

For the half ...

Question

For the half cell reaction,
$2 B r O_{3}^{-} + 12 H^{+} + 10 e \to B r_{2} + 6 H_{2} O$
the equivalent mass of sodium bromate is

Equal to its mol. mass

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1 / 3

of its mol. mass

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1 / 6

of its mol. mass

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1 / 5

of its mol. mass

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Solution

The correct option is D $1 / 5$ of its mol. mass
$2 B r O_{3}^{-} + 12 H^{+} + 10 e \to B r_{2} + 6 H_{2} O$
During the above conversion bromate changed the oxidation number from +5 to 0 when its converted to $B r_{2}$ .
So the equivalent weight is M/5
So the equivalent mass of sodium bromate is 1/5 of itsmolecular weight.
Hence option D is correct.

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For the half cell reaction,2BrO−3+12H++10e→Br2+6H2Othe equivalent mass of sodium bromate is

For the half cell reaction,
$2 B r O_{3}^{-} + 12 H^{+} + 10 e \to B r_{2} + 6 H_{2} O$
the equivalent mass of sodium bromate is