The Bohr's energy equation for H -atoms reveals that the energy level of a shell is given by E = - 13.58/n²eV. The smallest amount that an H-atoms will absorb, if in ground state is:

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For the hydrogen atom, the energy of the electron is defined by the factor En=−13.58/n2eV. Here n is positive integer. The minimum quantity of energy which it can absorb in its primitive stage is:

The correct option is C 10.19eVEn=−13.58n2In primitive stage at n=1,E1=−13.58eVMinimum energy in excited stage,n=2,E2=−3.395eVEnergy absorbed =−3.395+13.58=10.19eVHence, the correct option is D

For the hydrogen atom, the energy of the electron is defined by the factor $E_{n} = - 13.58 / n^{2} e V$ . Here n is positive integer. The minimum quantity of energy which it can absorb in its primitive stage is:

The correct option is C $10.19 e V$
$E_{n} = \frac{- 13.58}{n^{2}}$

In primitive stage at $n = 1, E_{1} = - 13.58 e V$

Minimum energy in excited stage,

$n = 2, E_{2} = - 3.395 e V$

Energy absorbed $= - 3.395 + 13.58 = 10.19 e V$

Hence, the correct option is D