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Standard X

Chemistry

Electronic Configuration

For the hydro...

Question

For the hydrogen atom, the energy of the electron is defined by the factor $E_{n} = - 13.58 / n^{2} eV$ . Here n is positive integer.
The minimum amount of energy that can be absorbed by hydrogen atom in its ground state is:

1.00 eV

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3.39 eV

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6.79 eV

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10.19 eV

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Solution

The correct option is D $10.19 eV$
The energy of the hydrogen atom is given by:
$E_{n} = \frac{- 13.58}{n^{2}}$
at $n = 1, E_{1} = - 13.58 eV$
Here, the minimum amount of energy that can be absorbed by hydrogen atom in its ground state is the energy required for transition of an electron from its $n = 1$ state to $n = 2$ state.
$n = 2, E_{2} = - 3.395 eV$
$Therefore, minimum energy = E_{2} - E_{1}$
$\Rightarrow - 3.395 + 13.58 = 10.19 eV$

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For the hydrogen atom, the energy of the electron is defined by the factor En=−13.58/n2 eV. Here n is positive integer. The minimum amount of energy that can be absorbed by hydrogen atom in its ground state is:

For the hydrogen atom, the energy of the electron is defined by the factor $E_{n} = - 13.58 / n^{2} eV$ . Here n is positive integer.
The minimum amount of energy that can be absorbed by hydrogen atom in its ground state is: