For the hypothetical reaction- the equilibrium constant k values are given A - B k - k 1 B - C k - k 2 C - D k - k 3What is the value of equilibrium constant for A - D -A- k 1- k 2- k 3B- k 1 k 2-3C- k 1 k 2- k 3D- k 1- k 2- k 3

The correct option is A k_1 × k_2 × k_3A → B k = k_1 B → C k = k_2 C → D k = k_3 A → D k = k_1 × k_2 × k_3 ...

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Byju's Answer

Standard XII

Chemistry

Law of Mass Action

For the hypot...

Question

For the hypothetical reaction, the equilibrium constant (k) values are given
$A \to B (k = k_{1}) B \to C (k = k_{2}) C \to D (k = k_{3})$
What is the value of equilibrium constant for $A \to D$ ?

k_{1} + k_{2} + k_{3}

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k_{1} \times k_{2} \times k_{3}

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\frac{k_{1} k_{2}}{3}

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\frac{k_{1} k_{2}}{k_{3}}

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Solution

The correct option is B $k_{1} \times k_{2} \times k_{3}$
$A \to B k = k_{1} B \to C k = k_{2} C \to D k = k_{3} A \to D k = k_{1} \times k_{2} \times k_{3}$

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For the hypothetical reaction, the equilibrium constant (k) values are given A→B(k=k1) B→C(k=k2)C →D(k=k3) What is the value of equilibrium constant for A→D ?

The correct option is B k1×k2×k3A→B k=k1B→C k=k2C→D k=k3A→D k=k1×k2×k3

For the hypothetical reaction, the equilibrium constant (k) values are given
$A \to B (k = k_{1}) B \to C (k = k_{2}) C \to D (k = k_{3})$
What is the value of equilibrium constant for $A \to D$ ?

The correct option is B $k_{1} \times k_{2} \times k_{3}$
$A \to B k = k_{1} B \to C k = k_{2} C \to D k = k_{3} A \to D k = k_{1} \times k_{2} \times k_{3}$