For the inversion of cane sugar- C 12 H 22 O 11 - H 2 O- C 6 H 12 O 6 - C 6 H 12 O 6- the rate constant is 2-12- 10 -4 L mol -1 sec -1 at 27 o C- The activation energy of the reaction is 1-07- 10 5 J mol -1- What is the rate constant of the reaction at 37 o C-

log( K 2.12× 10 ^ 4 #160; ) = 1.07× 10 ^ 5 2.303× 8.314 [ 1 300 1 310 #160; ] K=8.45× 10 ^ 4 mol ^ 1 L sec ^ 1 ...

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Arrhenius Equation

For the inver...

Question

For the inversion of cane sugar, $C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}$ , the rate constant is $2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}$ at $27^{o} C$ . The activation energy of the reaction is $1.07 \times 10^{5} J {m o l}^{- 1}$ . What is the rate constant of the reaction at $37^{o} C$ ?

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C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

{Δ H}_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b .}

C_{6} H_{12} O_{6} (s) = - 2816 k J {m o l}^{- 1}

{Δ H}_{f}^{o}

{C O}_{2} (g) = - 393.5 J {m o l}^{- 1}

{Δ H}_{f (H_{2} O)}^{o} = - 285.9 k J {m o l}^{- 1}

A g {N O}_{3}

{N H}_{4} O H

{A g}^{+} + e^{-} \to A g

E_{r e d}^{o} = 0.8 V

C_{6} H_{12} O_{6} + H_{2} O \to C_{6} H_{12} O_{7}

+ 2 H^{+} + 2 e^{-}

E_{r e d}^{o} = - 0.05 V

A g {({N H}_{3})}_{2} + e^{-} \to A g (s) + 2 {N H}_{3}

2.202 \times \frac{R T}{F} = 0.0592

\frac{F}{R T} = 38.92

298 K

2 {A g}^{+} + C_{6} H_{22} O_{6} + H_{2} O \to 2 A g (s) + C_{6} H_{212} O_{7} + 2 H^{+}

ln K

C_{6} H_{12} O_{6}

H_{2} O

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